# Coin Distribution Problem-Tcs Previous Year Qustions

Fri, 07 Aug, 2020

### Coin Distribution Problem

Problem Statement

Find the minimum number of coins required to form any value between 1 to N,both inclusive.Cumulative value of coins should not exceed N. Coin denominations are 1 Rupee, 2 Rupee and 5 Rupee.Let’s Understand the problem using the following example. Consider the value of N is 13, then the minimum number of coins required to formulate any value between 1 and 13, is 6. One 5 Rupee, three 2 Rupee and two 1 Rupee coins are required to realize any value between 1 and 13. Hence this is the answer.However, if one takes two 5 Rupee coins, one 2 rupee coin and two 1 rupee coin, then too all values between 1 and 13 are achieved. But since the cumulative value of all coins equals 14, i.e., exceeds 13, this is not the answer.

• Input Format:
• A single integer value.
• Output Format:
• Four space separated integer values.
• 1st – Total number of coins.
• 2nd – number of 5 Rupee coins.
• 3rd – number of 2 Rupee coins.
• 4th – number of 1 Rupee coins.
• Constraints:
• 0 < n < 1000

Refer the sample output for formatting

Sample Input

13

Sample Output

6 1 3 2

Explanation

• The minimum number of coins required is 6 with in it:
• minimum number of 5 Rupee coins = 1
• minimum number of 2 Rupee coins = 3
• minimum number of 1 Rupee coins = 2

Using these coins, we can form any value with in the given value and itself, like below:

Here the given value is 13

• For 1 = one 1 Rupee coin
• For 2 = one 2 Rupee coin
• For 3 = one 1 Rupee coin and one 2 Rupee coins
• For 4 = two 2 Rupee coins
• For 5 = one 5 Rupee coin
• For 6 = one 5 Rupee and one 1 Rupee coins
• For 7 = one 5 Rupee and one 2 Rupee coins
• For 8 = one 5 Rupee, one 2 Rupee and one 1 Rupee coins
• For 9 = one 5 Rupee and two 2 Rupee coins
• For 10 = one 5 Rupee, two 2 Rupee and one 1 Rupee coins
• For 11 = one 5 Rupee, two 2 Rupee and two 1 Rupee coins
• For 12 = one 5 Rupee, three 2 Rupee and one 1 Rupee coins
• For 13 = one 5 Rupee, three 2 Rupee and two 1 Rupee coins

## Java

``````
import java.util.*;
public class Main
{
public static void main (String[]args)
{
System.out.println ("Enter the Number");
Scanner s = new Scanner (System.in);
int number = s.nextInt ();
int one = 0, two = 0;
int five = (number - 4) / 5;
if (((number - 5 * five) % 2) == 0)
{
one = 2;
}
else
{
one = 1;
}
two = (number - 5 * five - one) / 2;
System.out.println (one + two + five);
System.out.println (five);
System.out.println (two);
System.out.println (one);

}
}
``````

## Python

``````
number = int (input ())
five = int ((number - 4) / 5) if ((number - 5 * five) % 2)== 0:
one = 2
else:
one = 1 two = (number - 5 * five - one)	//2
print (one + two + five, five, two, one)``````

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